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2102: full circle

issue 23 March 2013

Each of the four paired lights (at 1A/4, 13/14, 30/31 and 32/33) forms a RIGHT ANGLE which is the solution in each case. Four right angles equal THREE SIXTY DEGREES (the solutions at 23/40/15), thus making the FULL CIRCLE of the title.

First prize R.R. Alford, Oundle, Peterborough

Runners-up Jenny Atkinson, Little Chalfont, Bucks; Lewis Corner, South Fremantle, Western Australia

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